Odpowiedź:
Pb(OH)₂ + 2NaOH--> Na₂Pb(OH)₄
tetrahydroksyołowian(II)sodu
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Odpowiedź:
Pb(OH)₂ + 2NaOH--> Na₂Pb(OH)₄
tetrahydroksyołowian(II)sodu