Odpowiedź:
[tex]M_M_g_S_O___4=24+32+64=120 g/mol[/tex]
MMgNH4PO4=24+14+4+64+31=137g/mol
120g MgSO4--- 137g MgNH4PO4
xg - 1,37 g MgSO4-- 1,37g MgNH4PO4
137x=1,37*120
137x=164,4 /:137
x=1,2g = 1200mg MgSO4
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Odpowiedź:
[tex]M_M_g_S_O___4=24+32+64=120 g/mol[/tex]
MMgNH4PO4=24+14+4+64+31=137g/mol
120g MgSO4--- 137g MgNH4PO4
xg - 1,37 g MgSO4-- 1,37g MgNH4PO4
137x=1,37*120
137x=164,4 /:137
x=1,2g = 1200mg MgSO4