Na spadochorniarza wraz z ekwipunkiem dziala sila ciezkosci 1200 N i sila oporu powietrza o wartosci 800 N. Oblicz przyspieszenie z jakim spada spadochroniarz.
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masa = 1200/10=120
1200-800/120= 3 i 1/3m/s^2
masa: m = Q/g = 1200/10 =120kg
Z II zasady dynamiki; a = (Q - Fop) /m = (1200-800)/120 = 3.33m/s2