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CaCO3--->CaO+CO2
MCaCO3=100g/mol=0,1kg/mol
MCaO=40+16=56g/mol=0,056kg
2t=2000kg
0,1kg CaCO3----0,056kgCaO
xkg-----------------2000kg
x=3571,4kg=3,57tony
rozlozono 3,57 tony wapienia
mCaO=56u
CaCO3----->CaO + CO2
100g CaCO3-------56g CaO
xt CaCO3---------2t CaO
x=3,57 ton CaCO3 (wapienia)