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n = V*Cmol = 2mol/dm³*0,175dm³ = 0,35mola
2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂
54g------3mole
x----------y
Zn + H₂SO₄ → ZnSO₄ + 3H₂
65g-----------1mol
(15,7-x)--(0,35-y)
54y = 3x
65(0,35-y)= 15,7 - x
X= 54/3y = 18y
65*0,36 – 65y = 15,7 – 18y
22,75 - 65y = 15,7 -18y
65y -18y = 22,75 – 15,7
47y = 7,05
Y= 0,15
X= 18*0,15= 2,7g glinu
15,7g -2,7g = 13g cynku