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Etan - C2H6
Mcz.C2H6 = 2 x 12u + 6 x1u = 24u + 6u = 30u
% C2 = 2 x 12u = 24u x 100% : 30u = 80% węgla
Eten - C2H4
Mcz. C2H4 = 2 x 12u + 4 x 1u = 24u + 4u = 28u
% C2 = 24u x 100% : 28u = 85,71% węgla
Odp: Większy procent węgla zawiera eten - 85,71%.