Zadanie 3
a) (a+3b)(7a+2b) = 7a^2 + 2ab + 21ab + 6b^2 = 7a^2 + 23ab+6b^2
b) 5-(x+3)(x+1)= 5-(x^2+x+3x+3) =5-(x^2+4x+3) = 5-x^2-4x-3= -x^2-4x+2
c) t-(t+3)(t-5)= t-(t^2-5t+3t-15)=t-(t^2-2t-15)= t-t^2+2t+15=-t^2+3t+15
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Verified answer
Zadanie 3
a) (a+3b)(7a+2b) = 7a^2 + 2ab + 21ab + 6b^2 = 7a^2 + 23ab+6b^2
b) 5-(x+3)(x+1)= 5-(x^2+x+3x+3) =5-(x^2+4x+3) = 5-x^2-4x-3= -x^2-4x+2
c) t-(t+3)(t-5)= t-(t^2-5t+3t-15)=t-(t^2-2t-15)= t-t^2+2t+15=-t^2+3t+15