Odpowiedź:
13.
a ) = 2*(-1) - ( - 3) = -2 + 3 = 1
b) = [tex]\frac{4}{5} - 0,5 = 0,8 - 0,5 = 0,3[/tex]
c ) = [tex]-\frac{2}{5} + \sqrt[3]{\frac{64}{27} } = - \frac{2}{5} + \frac{4}{3} = - \frac{6}{15}+ \frac{12}{15} = \frac{6}{15} = \frac{2}{5}[/tex]
d ) = [tex]\frac{\sqrt[3]{27*3} }{-\sqrt[3]{3} } - \frac{2\sqrt[3]{3} }{-\sqrt[3]{3} } = - 3 + 2 = - 1[/tex]
e ) = [tex]\frac{- 2\sqrt[3]{2} }{5\sqrt[3]{2} } - \sqrt[3]{8} = - \frac{2}{5} - 2 = - 2 \frac{2}{5}[/tex]
f ) = [tex]\frac{\sqrt[5]{-32*4} }{-\sqrt[5]{4} } + \frac{-2}{-1} = 2 + 2 = 4[/tex]
===============================
14.
a ) z = 2 + 2*(-1) = 2 - 2 = 0
więc x*y*z = 0
------------------------------------------
b ) z = - 1 + 1 = 0
więc
x*y*z = 0
===============
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Odpowiedź:
13.
a ) = 2*(-1) - ( - 3) = -2 + 3 = 1
b) = [tex]\frac{4}{5} - 0,5 = 0,8 - 0,5 = 0,3[/tex]
c ) = [tex]-\frac{2}{5} + \sqrt[3]{\frac{64}{27} } = - \frac{2}{5} + \frac{4}{3} = - \frac{6}{15}+ \frac{12}{15} = \frac{6}{15} = \frac{2}{5}[/tex]
d ) = [tex]\frac{\sqrt[3]{27*3} }{-\sqrt[3]{3} } - \frac{2\sqrt[3]{3} }{-\sqrt[3]{3} } = - 3 + 2 = - 1[/tex]
e ) = [tex]\frac{- 2\sqrt[3]{2} }{5\sqrt[3]{2} } - \sqrt[3]{8} = - \frac{2}{5} - 2 = - 2 \frac{2}{5}[/tex]
f ) = [tex]\frac{\sqrt[5]{-32*4} }{-\sqrt[5]{4} } + \frac{-2}{-1} = 2 + 2 = 4[/tex]
===============================
14.
a ) z = 2 + 2*(-1) = 2 - 2 = 0
więc x*y*z = 0
------------------------------------------
b ) z = - 1 + 1 = 0
więc
x*y*z = 0
===============
Szczegółowe wyjaśnienie: