ma=-cx
ma+cx=0
ω²=c/m
T=2π/ω
f=1/T=ω/(2π)
DANE:
m2=4m1
ω1²=c/m1
ω2²=c/m2
ω1²/ω2²=m1/m2
ω1/ω2=√(m1/m2)=√(1/4)=1/2
f1/f2=ω1/ω2=1/2
ODP
f1/f2=1/2
Pozdrawiam
Hans
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
ma=-cx
ma+cx=0
ω²=c/m
T=2π/ω
f=1/T=ω/(2π)
DANE:
m2=4m1
ω1²=c/m1
ω2²=c/m2
ω1²/ω2²=m1/m2
ω1/ω2=√(m1/m2)=√(1/4)=1/2
f1/f2=ω1/ω2=1/2
ODP
f1/f2=1/2
Pozdrawiam
Hans