" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
W=Q
0,5 m^3 = 500 dm^3 = 500kg
c= cieplo wlasciwe - dla wody 4190 - do obliczen 4200
Q(na podneisienie temp o 30C) = cmT
Q=4200 x 500 x 30
Q= 63000 000J
Q= 63 000 kJ
63 000 kJ - 31420 kJ = 31580 kJ
nalezy dodatkowo dostarczyc 31580 kJ ciepla