Question

n1+n2+n3=36
n1*n2*n3=1440
Berapakah nilai dari n1, n2, dan n3 ?

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Answer 1

Penyelesaian

n1+n2+n3=36

n1*n2*n3=1440

n-b+n+n+b = 36

3n = 36

n = 36/3

n= 12.

( n-b ) ( n ) ( n + b ) = 1440

n(n² - b² ) = 1440

12(12² - b²) = 1440

1728 - 12b² = 1440

-12b² = 1440- 1728

= b² = -288/-12

[tex]b = \sqrt{24} = \sqrt[2]{6} [/tex]

[tex] n {1} = 12 - \sqrt[2]{6} [/tex]

[tex]n2 = 12[/tex]

[tex]n 3 = 12 + \sqrt[2]{6} [/tex]

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