" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
tenesmos un extremos Q(4,-6) y sabemos el punto medio R(-1,7) entre Q y S
entonces
-1=(4+x2)/2
-2=4+x2
x2=-6
7=(-6+y2)/2
14=-6+y2
y2=20
el.punto del segmento "S" es (-6,20)
prueba
R(x)=-6+4/2
R(x)=-2/2
R(x)=-1
R(y)=-6+20/2
R(y)=14/2
R(y)=7
R(-1,7)
comprobado
saludos