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f ' (x) = 4 x - 3 = 5; de modo que x = 2
Para x = 2, f(x) = 8
El punto de tangencia es P(2, 8)
La recta tangente es y - 8 = 5 (x - 2) = 5 x - 2
Finalmente y = 5 x - 2
Adjunto gráfico
Saludos Herminio