Dik:
∆Hf NH4Cl = -314 KJ/mol
∆Hf HCl = -92 KJ/mol
NH4Cl ➡ NH3 + HCl ∆H = 176 KJ
Besarnya ∆Hf NH3 adalah...
∆Hf NH4Cl = -314 KJ/mol
∆Hf HCl = -92 KJ/mol
NH4Cl ➡ NH3 + HCl ∆H = 176 KJ
Besarnya ∆Hf NH3 adalah...
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176 = ((1× △H NH3) + (1×(-92)) - (1×(-314))
176 = (△H NH3 + (-92)) + 314
(△H NH3 + (-92)) = 176 - 314
(△H NH3 + (-92)) = -138
△H NH3 = -138 + 92
△H NH3 = -46 kj/mol