Mol NH3 = 4,48/22,4 = 0,2
DeltaH reaksi = mol x deltaHs
= 0,2 mol x -104 kJ/mol
= - 20,8 kJ
Penguraian kebalikan dHf maka deltaH reaksi = + 20,8 kJ
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Mol NH3 = 4,48/22,4 = 0,2
DeltaH reaksi = mol x deltaHs
= 0,2 mol x -104 kJ/mol
= - 20,8 kJ
Penguraian kebalikan dHf maka deltaH reaksi = + 20,8 kJ