MOLE !!
Ile gramów kwasu borowego powstanie z 50g tritlenkudiboru ?
Dane:
H3BO3 - kwas borowy
B2O3 - tritlenekdiboru
Masa molowa H3BO3 = 3*1+11+3*16= 3+11+48=62g/mol
masa B2O3 = 50g
Masa molowa B2O3 = 2*11+3*16= 22+48= 70g/mol
50g x
B2O3 + 3 H2O ---> 2 H3BO3
1 mol 3mole 2 mole
70g/mol 2*62g/mol
50g - x
70g/mol - 2*62g/mol
70x= 2*62*50g
70x= 6200|/70
x=88,57g
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Dane:
H3BO3 - kwas borowy
B2O3 - tritlenekdiboru
Masa molowa H3BO3 = 3*1+11+3*16= 3+11+48=62g/mol
masa B2O3 = 50g
Masa molowa B2O3 = 2*11+3*16= 22+48= 70g/mol
50g x
B2O3 + 3 H2O ---> 2 H3BO3
1 mol 3mole 2 mole
70g/mol 2*62g/mol
50g - x
70g/mol - 2*62g/mol
70x= 2*62*50g
70x= 6200|/70
x=88,57g