Question

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titik didihnya jika 22,2 g CaCL2 (Mr= 111g/mol) di larutkan dalam 200g air (Kb=0,52°CKg/mol)

Answer 1

Verified answer

∆Tb = kb . w/Mr . 1000/p
∆Tb = 0,52 . 22,2/111 . 1000/200
∆Tb = 0,104 . 5
∆Tb = 0,52°C

∆Tb = Tb - Tb°
Tb = Tb° + ∆Tb
Tb = 100° + 0,52
Tb = 100,52°C