Question

Tentukan ∆H reaksi = C3H6 + H2 -> C3H8 jika :
C-H = 415 KJ/MOL
C=C = 615 KJ/MOL
C-C = 345 KJ/MOL
H-H = 432 KJ/MOL

Answer 1

Pemutusan
= 6 x C-H + 2 x C=C + C-C + 2 x H-H
= 6 x 415 + 2 x 345 + 345 + 2 x 432
= 4389 KJ/mol

pembentukan
= 8 x C-H + 2 x C-C
= 8 x 415 + 2 x 345
= 4010 KJ/mol

ΔH = 4389 - 4010 = 379 KJ/mol

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