Question

Kedalam 250 gram air dilarutkan 17,4 gram K_2 〖SO〗_4 . jika K_b air = 0,52°C/molal dan Ar K=39, S= 32, O=16 tentukanlah kenaikan titik didih larutan ?

Answer 1

Mr = (39*2) + (4.32) + (4.16)
     = 78 + 128 + 64
     = 270

ΔTb = kb * m * I
       = 0.52 * 17.4/270 * 1000/250 * 3
       = 0.52 * 0.64 * 4 * 3
       = 3.99⁰C

Tb=ΔTb+T₀
   = 3.99+100
   = 103.99⁰C