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mol = masa/Mm.
mol = 40 g / 249.7 g/mol = 0.16 mol
M = 0.16 mol / 2 L
M = 0.08 mol/L
2.Calcular la MOLALIDAD de una disolucion de 95 gramos de Acido nitrico (HNO3) en 2.5 litro de agua
Mm HNO3 = 63 g/mol
mol = 95 g / 63 g/mol = 1.508 mol
M = 1.508 mol / 2.5 L
M = 0.603 mol/L
3.Calcular la NORMALIDAD y la MOLARIDAD de 55 gramos de Na2CO3 en 100 ml de disolucion
Mm Na2CO3 = 106 g/mol
V = 100 / 1000 = 0.1 L
mol = 55 g / 106 g/mol
mol = 0.518
M= 0.518 mol/ 0.1 L
M = 5.18 mol/L
NORMALIDAD:
El Na2CO3 es una sal contiene 2
M = 2 N
DONDE N = M/2
N = 5.18 / 2 = 2.59 eq/L