Question

Hitunglah fraksi mol zat terlarut yg mengandung 18 persen massa glukosa,massa molar glukosa 180 gram/mol,massa molar air 18 g/mol.

Answer 1

18% = 18 gram glukosa
82% = 82 gram Air

mol glukosa = gr/Mr = 18/180 = 0,1 mol
mol air = gr/Mr = 82/18 = 4,56 mol
mol larutan = 0,1 + 4,56 = 4,66 mol 

fraksi mol zat terlarut