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ch3oh + 3/2o2 --> co2 + 2h2o
kita gunakan rumus
delta h={(sigma deltahf produk) - (sigma deltahf reaktan)}
delta h={(1.co2 + 2.h2o) - (1.ch3oh)}
delta h={(-394-572) - (-238)
delta h=-728 kj/mol
ditanya utk 3,2 gram, maka
n=m/mr
n=3,2/32
n=0,1 mol
jawabnya
0,1 mol x -728 kj/mol = -7280 kj