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C2H4 3O2 ⇒ 2CO2 +2H2O
ΔH = ((2×ΔHf CO2) + (2×ΔHfH2O)) - (( 1×ΔHfC2H4) +(3×ΔHf O2))
((2×(+393,5))+(2×(-285))) - ((1×(+52)) + (3×0))
(+787 - 570) - (+52)
+155 KJ