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NH3⇒N2+3H2 ΔH=-500Kj/mol
3(N-H)⇒ 946+3(436)
3(N-H)⇒946+1308
EI=EI R-EIP
-500=3(N-H) - 2254
2254-500=3(N-H)
1754=3(N-H)
584,7=N-H