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M tego alkenu(CxHx) = 70g/mol
70g (alkenu) - 100%
xg(wodoru) - 14,2%
x= 9,94g ≈ 10g , a więc => CxH₁₀
(ponieważ M wodoru=1g/mol)
70g/mol- 10g/mol= 60g/mol
M węgla= 12g/mol , a więc => 60g/mol: 12g/mol = 5
Odp. C₅H₁₀