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P₁ = 3 × 10⁵
P₂ = 4 × 10⁵
R = 8,31 J/mol
n = 2 mol
* Isokhorik
T₂ = 400 K
ΔU = nRΔT
= x 2 x 8.31 x (T₂-T₁)
= x 2 x 8.31 x 100
= 2493 J