Question

H₂ + 1/2 O₂ ⇒--⇒ H₂O ΔH = -242 KJ
diketahui energi ikatan H-H dan O-O masing-masing 436 dan 500 kj /mol . Hitunglah energi ikatan rata-rata H-O

Answer 1

Saya hanya mengira2.. 
H-H + O-O --> H-O-H 
436+500 - 2 O-H = -242
936 - 2 O-H = -242
-2 O-H = -242-936
-2 O-H = -1178
O-H = -1178/-242
O-H = 589

Answer 2

-242 = 2(H-O) - [(H-H) + ( O-O)]
-242 = 2(H-O) - [436 + 500]
-242 = 2 (H-O) -936
2(H-O) = 694
H-O = 347 KJ/MOL