Question

1.
Diketahui energi
ikatan:

C – C = 348 kJ/mol Cl – Cl = 242 kJ/mol

H – Cl = 431 kJ/mol C – Cl = 328 kJ/mol

C – H = 423 kJ/mol

Besarnya ΔH pada reaksi yg di gambar yg saya lampirkan ..

Answer 1

3 dC-H = 3 * 423 + 1 d C-C +2 dC-H+ 1 dC-C +3 dC-H+ 1 d Cl-Cl
           = 1269 + 348 +846 +348 +1269 + 242 = 4322 ( kiri)
3 dC-H = 3 * 423 + 1 d C-C + 1 d C-Cl + 1 d C-H + 1 d C-C + 3 d C-H
           = 1269 + 348 + 328 + 423 + 348 + 1269 = 3985 ( kanan )
Karena energi ikatan,maka rumusnya = kiri - kanan = 4322 - 3985 = + 337 kj / mol