Question

O-H : 436 kJ/mol
O=O : 146 kJ/mol
H-H : 436 kJ/mol
H-Cl : 431 kJ/mol
Cl-Cl : 242 kJ/mol
Berapakah H°d HCl (entalpi penguraian)

Answer 1

2HCl⇒ H2 +Cl2
perubahan entalpi
(reaktan)-(produk)
(2. H-Cl)-(H-H+Cl-Cl)
(2.431)-(436+242)
862-678= 184 kJ/ mol

*maaf klo salah