holaa
masa molar = 1+14+16*3= 63g/mol
63g/mol=100%
14g=X
X=14*100/63
x= 22,2%
la D
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holaa
masa molar = 1+14+16*3= 63g/mol
63g/mol=100%
14g=X
X=14*100/63
x= 22,2%
la D