Question

mohon.bantuannya mnegnai integral

Answer 1

Int (6x-2)(6x²-4x+1)² dx
Dengan:
u = 6x²-4x+1
du = 12x-4 dx
Maka,
1/2 du = 6x - 2 dx

Didapat:
int 1/2 u² du
= 1/2 x 1/3 x u³ + C
= 1/6 u³ + C

Substitusi ulang:
= 1/6 (6x²-4x+1)³ + C [B]