Question

mohon yah kak bantuan nya​

Answer 1

80°C

Penjelasan:

m = 400 g = 0,4 Kg

Q = 9.360 J

c = 390 J/kg.°C

suhu awal = 20°C

Q = m x c x ∆t

∆t = Q : (m x c)

= 9.360 : (0,4 x 390)

= 9.360 : 156

= 60°C

∆t = suhu akhir - suhu awal

suhu akhir = suhu awal + ∆t

= 20°C + 60° C

= 80°C