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ΔH1 + ΔH4 = ΔH2 + ΔH3
ΔH1 + 60 kJ = 120 kJ + 45 kJ
ΔH1 + 60 kJ = 165 kJ
ΔH1 = (165 - 60) kJ
ΔH1 = 105 kJ ---> D
ΔH1 + 60 Kj/mol = 120Kj/mol + 45 Kj/mol
ΔH1 = 120 Kj/mol + 45 KJ/mol - 60Kj/mol
ΔH1 = 165 Kj/mol - 60Kj/mol
ΔH1 = 105 Kj/mol