R = 10/2 = 5 CM
MAKA :
V = 1/3πR²T
= 1/3(3,14(5²(13)
= 1/3(3,14(25(13)
= 1/3(3,14(325)
= 1/3(1.020,5)
= 1.020,5/3
= 340,16 CM³
d = r × 2
r = d/2
r = 10/2
r = 5 cm
Volume kerucut
V = ⅓ × πr²t
V = ⅓ × 3,14 × 5² × 13
V = ⅓ × 3,14 × (5 × 5) × 13
V = ⅓ × 3,14 × 25 × 13
V = ⅓ × 78,5 × 13
V = ⅓ × 1.020,5
V = 1.020,5/3
V = 340,16 cm³
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R = 10/2 = 5 CM
MAKA :
V = 1/3πR²T
= 1/3(3,14(5²(13)
= 1/3(3,14(25(13)
= 1/3(3,14(325)
= 1/3(1.020,5)
= 1.020,5/3
= 340,16 CM³
d = r × 2
r = d/2
r = 10/2
r = 5 cm
Volume kerucut
V = ⅓ × πr²t
V = ⅓ × 3,14 × 5² × 13
V = ⅓ × 3,14 × (5 × 5) × 13
V = ⅓ × 3,14 × 25 × 13
V = ⅓ × 78,5 × 13
V = ⅓ × 1.020,5
V = 1.020,5/3
V = 340,16 cm³