Question

Mohon jawaban(1) Tentukan fraksi mol glukosa dalam larutan glukosa 10%(M,glukosa=180)

Answer 1

Mr Glukosa = 180
Mr Air = 18

Asumsikan => Massa Larutan Glukosa = 100 gram

Kadar Glukosa = 10%

Massa Glukosa dalam Larutan
= 10% × 100 gram
= 10 gram

Massa Air = 100 gram - 10 gram = 90 gram

n Glukosa
= massa / Mr
= 10 gram / 180
= 0,0555 mol

n Air
= massa / Mr
= 90 gram / 18
= 5 mol

n total = 5,055 mol

Fraksi mol Glukosa (X Glukosa)
= n glukosa / n total
= 0,055 mol / 5,055 mol
= 0,011

Fraksi mol Air (X Air)
= n Air / n total
= 5 mol / 5,055 mol
= 0,989