#F
[ (2 a⁵ b )/(16 a² b⁴) ]⁻¹
= (16 a² b⁴)/(2a⁵ b]
= (16/2) (a²/a⁵) (b⁴/b)
= (8) (1/a³)(b³)
= (8 b³)/(a³)
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#F
[ (2 a⁵ b )/(16 a² b⁴) ]⁻¹
= (16 a² b⁴)/(2a⁵ b]
= (16/2) (a²/a⁵) (b⁴/b)
= (8) (1/a³)(b³)
= (8 b³)/(a³)