Jawab:
Tallibusur
sudut dalam 4 talibusur
sudut berhadapan berjumlah 180
Penjelasan dengan langkah-langkah:
<BAD + <BCD = 180
<BCD = 180 - <BAD
cos< BCD = cos(180 - <BAD)
cos <BCD = - cos <BAD
.
BD² = CD² + BC² - 2. CD. BC. cos <BCD
BD² = CD² + BC² - 2. CD. BC. (- cos <BAD)
BD² = CD² + BC² + 2. CD. BC. cos <BAD...(i)
BD² = AB² + AD² - 2 . AB. AD. cos <BAD ..(ii) ....(-)
0 = (9-1) + (4- 16) + 2. 3. 2. cos <BAD +2 .1. 4. cos <BAD
0 = 8 - 12 + 12 cos < BAD + 8 cos <BAD
4 = 20 cos <BAD
cos <BAD = 4/20 = 1/5
Ikutan .. :)
BCD + BAD = 180°
BD² = BD²
AB² + AD² - 2.AB.AD cos BAD = BC² + CD² - 2.BC.CD cos BCD
1² + 4² - 2.1.4 cos BAD = 2² + 3² - 2.2.3 . (- cos BAD)
17 - 8 cos BAD = 13 + 12 cos BAD
17 - 13 = 8 cos BAD + 12 cos BAD
20 cos BAD = 4
cos BAD = 4/20
cos BAD = 1/5 ✔
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Verified answer
Jawab:
Tallibusur
sudut dalam 4 talibusur
sudut berhadapan berjumlah 180
Penjelasan dengan langkah-langkah:
<BAD + <BCD = 180
<BCD = 180 - <BAD
cos< BCD = cos(180 - <BAD)
cos <BCD = - cos <BAD
.
BD² = CD² + BC² - 2. CD. BC. cos <BCD
BD² = CD² + BC² - 2. CD. BC. (- cos <BAD)
BD² = CD² + BC² + 2. CD. BC. cos <BAD...(i)
BD² = AB² + AD² - 2 . AB. AD. cos <BAD ..(ii) ....(-)
0 = (9-1) + (4- 16) + 2. 3. 2. cos <BAD +2 .1. 4. cos <BAD
0 = 8 - 12 + 12 cos < BAD + 8 cos <BAD
4 = 20 cos <BAD
cos <BAD = 4/20 = 1/5
Verified answer
Ikutan .. :)
BCD + BAD = 180°
BD² = BD²
AB² + AD² - 2.AB.AD cos BAD = BC² + CD² - 2.BC.CD cos BCD
1² + 4² - 2.1.4 cos BAD = 2² + 3² - 2.2.3 . (- cos BAD)
17 - 8 cos BAD = 13 + 12 cos BAD
17 - 13 = 8 cos BAD + 12 cos BAD
20 cos BAD = 4
cos BAD = 4/20
cos BAD = 1/5 ✔