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jawaban soal nomer 20
f(x) = x(x + 500/x - 40)
= x² + 500 - 40x
= x² - 40x + 500
turunan fungsi f'(x)
f'(x) = 2x - 40
0 = 2x - 40
40 = 2x
40/2 = x
20 = x
nilai minimum
f(20) = x² - 40x + 500
= (20)² - 40(20) + 500
= 400 -800 + 500
= 100 juta rupiah