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banyaknya = 2^4 = 16
b) A = {P₁ , P₂}
c) A = {P₁} atau A = {P₂}
2) 5C2 = 5!/3!2!
= 10
5C1 = 5!/4!1!
= 5
banyak kemungkinan = 5 pasang
b 2/6 =1/8
c. 1/16