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Verified answer
Α+β= - -4/3= 4/3αβ= 2/3
Akar2 baru: (3α+1) dan (3β+1)
Jumlah= (3α+1)+(3β+1)= 3 (α+β) + 2 = 3.4/3 + 2 = 6
Hasil kali= (3α+1)(3β+1)= 9αβ+3(α+β)+1= 9.2/3 + 3.4/3 + 1 = 6+4+1= 11
Persamaan baru: x^2 -6x+11=0