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titik A = (-12, 0) → (x1, y1)
titik B = (0, 9) → (x2, y2)
a × b = ?
masukkan titik A dan B ke persamaan garis AB,
titik A :
x1/4a + y1/3b = 1
(-12)/4a + (0)/3b = 1
-3/a + 0 = 1
-3/a = 1
-3 = 1 × a
-3 = a
titik B :
x2/4a + y2/3b = 1
(0)/4a + (9)/3b = 1
0 + 3/b = 1
3/b = 1
3 = 1 × b
3 = b
a × b = -3 × 3 = -9
maaf kalau salah
semoga membantu