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=3*40+2(31+4*16)
=310
b.MrCO(NH2)2=ArC+2(ArN+2*ArH)
=12+2(14+2*1)
=44
2.a. mol=masa/Ar/Mr=32/32=1
v=mol*22.4=1*22.4+22.4L
b. PV=nRT
v=1*0.0821*(27+273)/1
=24.63L
3. 2/1=3/x x=3/2=1.5 x= co=co2
4. konfigurasi elektron b = 2 8 6