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1) f(x) = 2x + m
f(3) = 4
artinya
f(3) = 2(3) + m = 4
= 6 + m = 4
m = 4 - 6
m = -2
sehingga f(x) = 2x - 2
2)
f(x) = ax + b
f(1) = 2
f(2) = 1
artinya
f(1) = a(1) + b = 2
f(2) = a(2) + b = 1
maka dengan metode eleminasi didapatkan
a + b = 2
2a + b = 1 -
-a = 1 ---> a = -1
pilihlah salah satu persamaan antara a + b = 2 atau 2a + b = 1
*disini saya memilih a + b = 2*
a + b = 2
-1 + b = 2
b = 2 + 1
b = 3
sehingga yang tadinya f(x) = ax + b sekarang menjadi
f(x) = -x + 3
f(x - 1) = -(x - 1) + 3
f(x - 1) = -x + 4
f(x) + f(x - 1) = -x + 3 + -x + 4
f(x) + f(x - 1) = -2x + 7
mungkin segitu dulu, semoga membantu