Question

Mohon bantuannya ya kakak no berapa aja kecuali no 1

Answer 1

Verified answer

Jawab
(3)
h = 6m
r= 2/3 
panjang lintasan  = (3+2)/(3-2) x 6m = 30 m

(7)
y = x^3 -6x^2 +9x - 15
y' = 3x^2 -12x + 9

(8) 
y = x^3 -12x^2  36x - 15
y; = 0
3x^2 - 24x + 36= 0
x^2 - 8x  +12 =0
(x - 6)(x  -2) =0
x = 6 atau x = 2

x=6 ,  y = 6^3 - 12.6^2 +36(6) - 15 = -15
x= 2 , y = 2^3- 12. 2^2 + 36(2) - 15 = 41
minimum = -15
maksimum = 41

(9)
f(x)= (3x+2)(x-5)
f(x)= 3x^2 -13x -10
absis 1 --> x= 1
f(1) = 3-13 -10
f(1)= -20
titik singgung (1, -20)

gradien m = y1' =  6x -13
x= 1 , m -= 6(1) - 13
m = -7

y - y1 = m (x -x 1)
y + 20  =  - 7(x - 1)
y = -6x + 7 -20
y = -6x - 13

(10) Panjang kawat = 24
4x+ 3y = 24
4x = 24- 3y
2x = 12  - 3/2 y

Luas =  2(xy)
L = 2 x.y
L = (12 - 3/2 y)y
L(y) = 12 y - 3/2 y^2
L '(y) = 0
12 - 3y = 0
3y = 12
y = 4

4x+ 3y = 24
4x + 12 = 24
4x = 12
x = 3

ukuran x = 3 dan ukuran y = 4