Question

mohon bantuannya ya kak​

Answer 1

Jawaban:

2x+3y-5=0

3y=-2x+5

masing-masing kiri dan kanan dibagi 3

y=-2/3x+5/3

m1=-2/3

m1=m2=-2/3(sejajar)

(6,4)

x1 y1

y-y1=m(x-x1)

y-4=-2/3(x-6)

3(y-4)=-2(x-6)

3y-12=-2x+12

2x+3y-12-12=0

2x+3y=-24=0 (A)

y=2x+5

m1=2

m1×m2=-1

2×m2=-1

m2=-1/2

(4,3)

x1 y1

y-y1=m(x-x1)

y-3=-1/2(x-4)

2(y-3)=-1(x-4)

2y-6=-x+4

x+2y-6-4=0

x+2y-10=0 (C)

Penjelasan dengan langkah-langkah:

Semoga membantu...