Mohon bantuannya ya kak.... Question from @maykelcari126

JavierSKho13

Penjelasan dengan langkah-langkah:

PERBANDINGAN

1. b

Abang = A

Enda = E

IndRi = R

E : A = 5 : 2

A : R = 3 : 4

E : A : R = 15 : 6 : 8

E + A + R = 116

silisih umur Enda dan Indri

= (15 – 8) × 116

15+6+8

= 7 × 116

= 7 × 4

= 28 tahun ✔

3. b

20 × 5 = 25 × p

100 = 25p

p = 100

p = 4 anak ✔

4. b

125 × 6 = (125 + 25) × h

750 = 150h

h = 750

150

h = 5 hari ✔

2 votes Thanks 1

TheManOfMath

Penjelasan dengan langkah-langkah:

Penyelesaian :

$[tex]5 \div 2 = e \div a \\ 3 \div 4 = a \div i \\ = 15 \div 6 \div 8 = e \div a \div i \\ = 116$

$[tex]5 \div 2 = e \div a \\ 3 \div 4 = a \div i \\ = 15 \div 6 \div 8 = e \div a \div i \\ = 116$ $selisih \: e \: dan \: i \\ = \frac{15 - 8}{15 + 6 + 8} \times 116 \\ = \frac{7}{29} \times 116 \\ = 7 \times \frac{116}{29} \\ = 7 \times 4 \\ = 28 \: t$ [/tex]

$= 20 \times 5 \\ = 100 = 25p \\ = \frac{100}{5} = 4 \\ p = 4 \: anak$

$750 = 150 \: h \\ = \frac{750}{150} = 5 \\ = 5 \: hari$

2 votes Thanks 3

= 28 tahun ✔

p = 4 anak ✔

h = 5 hari ✔

Recommend Questions

Life Enjoy

Get in touch

Social