Mohon bantuannya :) tentukan limit x mendekati 1 dari √(x^2+x-1 ) - √(2x-1 ) per √(x+3)

October 2018 1 78 Report

Mohon bantuannya :)
tentukan limit x mendekati 1 dari √(x^2+x-1 ) - √(2x-1 ) per √(x+3) – 2

izharulhaq78 $\lim_{x\to1}\frac{\sqrt{x^2+x-1}-\sqrt{2x-1}}{\sqrt{x+3}-2}\\\lim_{x\to1}\frac{\sqrt{x^2+x-1}-\sqrt{2x-1}}{\sqrt{x+3}-2}\times\frac{\sqrt{x^2+x-1}+\sqrt{2x-1}}{\sqrt{x^2+x-1}+\sqrt{2x-1}}\\\lim_{x\to1}\frac{(\sqrt{x^2+x-1})^2-(\sqrt{2x-1})^2}{(\sqrt{x+3}-2)(\sqrt{x^2+x-1}+\sqrt{2x-1})}\\\lim_{x\to1}\frac{(x^2+x-1)-(2x-1)}{(\sqrt{x+3}-2)(\sqrt{x^2+x-1}+\sqrt{2x-1})}\\\lim_{x\to1}\frac{x^2+x-1-2x+1}{(\sqrt{x+3}-2)(\sqrt{x^2+x-1}+\sqrt{2x-1})}$
$\lim_{x\to1}\frac{x^2-x}{(\sqrt{x+3}-2)(\sqrt{x^2+x-1}+\sqrt{2x-1})}\times\frac{\sqrt{x+3}+2}{\sqrt{x+3}+2}\\\lim_{x\to1}\frac{(x^2-x)(\sqrt{x+3}+2)}{((\sqrt{x+3})^2-2^2)(\sqrt{x^2+x-1}+\sqrt{2x-1})}\\\lim_{x\to1}\frac{(x^2-x)(\sqrt{x+3}+2)}{((x+3)-4)(\sqrt{x^2+x-1}+\sqrt{2x-1})}\\\lim_{x\to1}\frac{x(x-1)(\sqrt{x+3}+2)}{(x+3-4)(\sqrt{x^2+x-1}+\sqrt{2x-1})}\\\lim_{x\to1}\frac{x(x-1)(\sqrt{x+3}+2)}{(x-1)(\sqrt{x^2+x-1}+\sqrt{2x-1})}\\\lim_{x\to1}\frac{x(\sqrt{x+3}+2)}{\sqrt{x^2+x-1}+\sqrt{2x-1}}$
$\frac{1(\sqrt{1+3}+2)}{\sqrt{1^2+1-1}+\sqrt{2(1)-1}}\\\frac{\sqrt{4}+2}{\sqrt{1}+\sqrt{2-1}}\\\frac{2+2}{1+\sqrt{1}}\\\frac{4}{1+1}\\\frac{4}{2}\\\boxed{2}$

0 votes Thanks 2

aininia terima kasih

Jelaskan perbedaan antara rumusan masalah dan rumusan hipotesis

Tolong bantu ya ^^faktor apakah yang menyebabkan atom melepaskan elektron dan menangkap elektron?

Jika 3 log 5 = m dan 7 log 3 = n, maka nyatakan 35 log 15/7 dalam m dan n!

Recommend Questions

Life Enjoy

Get in touch

Social