Question

Mohon bantuannya saya masih kurang paham soal ada di gambar

Answer 1

3x²+6x+2=0
p+q = -6/3 = -2
p.q = 2/3

(p²-q²)²+p²+q² = ((p+q)(p-q))²+(p²+q²)
= ((p+q)².(p-q)²)+(p+q)²-2pq
= ((p+q)².(p²+q²-2pq))+(p+q)²-2pq
= ((p+q)².(((p+q)²-2pq)-2pq))+(p+q)²-2pq
= ((p+q)².((p+q)²-4pq)+(p+q)²-2pq

(substitusi nilai yang ada)

= ((-2)².(-2)² - 4(2/3))+(-2)²-2(2/3)
= (4.(4 - 8/3))+ 4 - 4/3
= (4.(4/3))+ 4 - 4/3
= 16/3 + 4 - 4/3
= 16/3 + 12/3 - 4/3
=(16+12-4)/3
= 24/3
=8