Question

Mohon bantuannya makasih :)

diketahui = f(2)=5
f(5)=8

rumus f(x)=ax+b

maka nilai dari f(10)=???

Answer 1

F(2) = ax + b = 5
        a(2)+ b = 5
        2a + b = 5

f(5) = ax + b = 8
         a(5) + b = 8
         5a + b = 8

2a + b = 5
5a + b = 8
---------------- _
-3a     = -3
   a     = 1

2a + b = 5
2(1) + b = 5
2    + b = 5
        b = 5 - 2
        b = 3

f(10) = ax + b 
       = 1.10 + 3
       = 13

Answer 2

Cari nilai a :


Cari nilai b :


Sehingga, nilai f(10) :