[tex] \tt = \frac{ \sqrt[3]{a \sqrt{a} } }{a} [/tex]
[tex] \tt = {(a. \sqrt{a} )}^{ \frac{1}{3} } \times {a}^{ - 1} [/tex]
[tex] \tt = {(a. {a}^{ \frac{1}{2} }) }^{ \frac{1}{3} } \times {a}^{ - 1} [/tex]
[tex] \tt = {( {a}^{1 + \frac{1}{2} }) }^{ \frac{1}{3} } \times {a}^{ - 1} [/tex]
[tex] \tt = {( {a}^{ \frac{3}{2} } )}^{ \frac{1}{3} } \times {a}^{ - 1} [/tex]
[tex] \tt = {a}^{ \frac{3}{6} } \times {a}^{ - 1} [/tex]
[tex] \tt = {a}^{ \frac{1}{2} } \times {a}^{ - \frac{2}{2} } [/tex]
[tex] \tt = {a}^{ - \frac{1}{2} } [/tex]
Jawaban B.) [tex] \tt {a}^{-\frac{1}{2}} [/tex]
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[tex] \tt = \frac{ \sqrt[3]{a \sqrt{a} } }{a} [/tex]
[tex] \tt = {(a. \sqrt{a} )}^{ \frac{1}{3} } \times {a}^{ - 1} [/tex]
[tex] \tt = {(a. {a}^{ \frac{1}{2} }) }^{ \frac{1}{3} } \times {a}^{ - 1} [/tex]
[tex] \tt = {( {a}^{1 + \frac{1}{2} }) }^{ \frac{1}{3} } \times {a}^{ - 1} [/tex]
[tex] \tt = {( {a}^{ \frac{3}{2} } )}^{ \frac{1}{3} } \times {a}^{ - 1} [/tex]
[tex] \tt = {a}^{ \frac{3}{6} } \times {a}^{ - 1} [/tex]
[tex] \tt = {a}^{ \frac{1}{2} } \times {a}^{ - \frac{2}{2} } [/tex]
[tex] \tt = {a}^{ - \frac{1}{2} } [/tex]
Jawaban B.) [tex] \tt {a}^{-\frac{1}{2}} [/tex]
@BeruangGemoy :•